Recall:
- Displacement:
Dx = xf - xi
- Average velocity:
vavg = Dx / Dt
- Instantaneous velocity: the average velocity in the limit the time interval goes to zero,
also the slope on the position versus time graph.
- Average acceleration:
aavg = Dv / Dt
= (vf-vi)/(tf-ti). Note that
vf and vi are instantaneous velocities.
Example: P2.16
A car is travelling initially at +7.0m/s. It accelerates at a
rate of +0.80m/s2 for 2.0s. What is the final
velocity?
- Read the problem.
- Make a sketch.
- Identify the data: vi = 7.0m/s, a = 0.80m/s2,
Dt = 2.0s.
- We will use the equation a = (vf - vi)
/ Dt
- Rewrite the equation to solve for vf = vi
+ aDt = 7.0m/s + (0.80m/s2)(2.0s)
= 8.6m/s
- Check the answer.
Motion Diagram
1-D Motion with Constant Acceleration
Free Fall
Chapter 3: Vectors and 2-D Motion
Vectors and Scalars
Some Properties of Vectors
Components of a Vector